Product Code Database
Example Keywords: grand theft -produce $10-153
   » » Wiki: Ideal Norm
Tag Wiki 'Ideal Norm'.
Tag

Ideal norm
 (

 C O N T E N T S 
Rank: 100%
Bluestar Bluestar Bluestar Bluestar Blackstar

In commutative algebra, the norm of an ideal is a generalization of a of an element in the . It is particularly important in since it measures the size of an ideal of a complicated in terms of an ideal in a less complicated ring. When the less complicated number ring is taken to be the ring of integers, Z, then the norm of a nonzero ideal I of a number ring R is simply the size of the finite R/ I.


Relative norm
Let A be a with field of fractions K and of B in a finite separable extension L of K. (this implies that B is also a Dedekind domain.) Let \mathcal{I}_A and \mathcal{I}_B be the of A and B, respectively (i.e., the sets of nonzero .) Following the technique developed by Jean-Pierre Serre, the norm map
N_{B/A}\colon \mathcal{I}_B \to \mathcal{I}_A
is the unique group homomorphism that satisfies
N_{B/A}(\mathfrak q) = \mathfrak{p}^{B/\mathfrak}
for all nonzero \mathfrak q of B, where \mathfrak p = \mathfrak q\cap A is the of A lying below \mathfrak q.

Alternatively, for any \mathfrak b\in\mathcal{I}_B one can equivalently define N_{B/A}(\mathfrak{b}) to be the of A generated by the set \{ N_{L/K}(x) | x \in \mathfrak{b} \} of of elements of B.

For \mathfrak a \in \mathcal{I}_A, one has N_{B/A}(\mathfrak a B) = \mathfrak a^n, where n = L.

The ideal norm of a is thus compatible with the field norm of an element:

N_{B/A}(xB) = N_{L/K}(x)A.

Let L/K be a of with rings of integers \mathcal{O}_K\subset \mathcal{O}_L.

Then the preceding applies with A = \mathcal{O}_K, B = \mathcal{O}_L, and for any \mathfrak b\in\mathcal{I}_{\mathcal{O}_L} we have

N_{\mathcal{O}_L/\mathcal{O}_K}(\mathfrak b)= K \cap\prod_{\sigma \in \operatorname{Gal}(L/K)} \sigma (\mathfrak b),
which is an element of \mathcal{I}_{\mathcal{O}_K}.

The notation N_{\mathcal{O}_L/\mathcal{O}_K} is sometimes shortened to N_{L/K}, an abuse of notation that is compatible with also writing N_{L/K} for the field norm, as noted above.

In the case K=\mathbb{Q}, it is reasonable to use positive as the range for N_{\mathcal{O}_L/\mathbb{Z}}\, since \mathbb{Z} has trivial ideal class group and \{\pm 1\}, thus each nonzero of \mathbb{Z} is generated by a uniquely determined positive . Under this convention the relative norm from L down to K=\mathbb{Q} coincides with the defined below.


Absolute norm
Let L be a number field with ring of integers \mathcal{O}_L, and \mathfrak a a nonzero (integral) ideal of \mathcal{O}_L.

The absolute norm of \mathfrak a is

N(\mathfrak a) :=\left =\left|\mathcal{O}_L/\mathfrak a\right|.\,
By convention, the norm of the zero ideal is taken to be zero.

If \mathfrak a=(a) is a , then

N(\mathfrak a)=\left|N_{L/\mathbb{Q}}(a)\right|.

The norm is completely multiplicative: if \mathfrak a and \mathfrak b are ideals of \mathcal{O}_L, then

N(\mathfrak a\cdot\mathfrak b)=N(\mathfrak a)N(\mathfrak b).

Thus the absolute norm extends uniquely to a group homomorphism

N\colon\mathcal{I}_{\mathcal{O}_L}\to\mathbb{Q}_{>0}^\times,
defined for all nonzero of \mathcal{O}_L.

The norm of an ideal \mathfrak a can be used to give an upper bound on the field norm of the smallest nonzero element it contains:

there always exists a nonzero a\in\mathfrak a for which

\left|N_{L/\mathbb{Q}}(a)\right|\leq \left ( \frac{2}{\pi}\right )^s \sqrt{\left|\Delta_L\right|}N(\mathfrak a),
where

* \Delta_L is the discriminant of L and
* s is the number of pairs of (non-real) complex of into \mathbb{C} (the number of complex places of ).


See also

Page 1 of 1
1
Page 1 of 1
1

Account

Social:
Pages:  ..   .. 
Items:  .. 

Navigation

General: Atom Feed Atom Feed  .. 
Help:  ..   .. 
Category:  ..   .. 
Media:  ..   .. 
Posts:  ..   ..   .. 

Statistics

Page:  .. 
Summary:  .. 
1 Tags
10/10 Page Rank
5 Page Refs